(1+2x)(x^2-3x+1)=

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Solution for (1+2x)(x^2-3x+1)= equation: 


Simplifying
(1 + 2x)(x2 + -3x + 1) = 0

Reorder the terms:
(1 + 2x)(1 + -3x + x2) = 0

Multiply (1 + 2x) * (1 + -3x + x2)
(1(1 + -3x + x2) + 2x * (1 + -3x + x2)) = 0
((1 * 1 + -3x * 1 + x2 * 1) + 2x * (1 + -3x + x2)) = 0
((1 + -3x + 1x2) + 2x * (1 + -3x + x2)) = 0
(1 + -3x + 1x2 + (1 * 2x + -3x * 2x + x2 * 2x)) = 0
(1 + -3x + 1x2 + (2x + -6x2 + 2x3)) = 0

Reorder the terms:
(1 + -3x + 2x + 1x2 + -6x2 + 2x3) = 0

Combine like terms: -3x + 2x = -1x
(1 + -1x + 1x2 + -6x2 + 2x3) = 0

Combine like terms: 1x2 + -6x2 = -5x2
(1 + -1x + -5x2 + 2x3) = 0

Solving
1 + -1x + -5x2 + 2x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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